已知(2x-y)(2x+y)=-5/2(2y²-64/5),2x(y-1)+4(1/2x-1)=0.求下列各式的值 (1)(x-y)²(2)x四次方+y四次方-2x²y²
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已知(2x-y)(2x+y)=-5/2(2y²-64/5),2x(y-1)+4(1/2x-1)=0.求下列各式的值 (1)(x-y)²(2)x四次方+y四次方-2x²y²
已知(2x-y)(2x+y)=-5/2(2y²-64/5),2x(y-1)+4(1/2x-1)=0.
求下列各式的值
(1)(x-y)²
(2)x四次方+y四次方-2x²y²
已知(2x-y)(2x+y)=-5/2(2y²-64/5),2x(y-1)+4(1/2x-1)=0.求下列各式的值 (1)(x-y)²(2)x四次方+y四次方-2x²y²
先;有上面两式得出X^2+y^2=8 2XY=4 这是由上面化简出来的
然后由(X-Y)^2=x^2+y^2-2xy 吧上面代入就可以得到(1)的值为4
(2)X^4+Y^4=(X^2+Y^2)^2-2X^Y^2
SO; X^4+Y^4-2X^2Y^2=(X^2+Y^2)^2-4X^2Y^2=(X^2+Y^2)^2-(2xy)^2
把上面算得的代入就能得到(2) 的值为48
希望能够帮到你!
先解二元方程 求出xy的值 然后代入就行
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