x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
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x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
即2x+3y=21 (1)
2x+5y=27 (2)
(2)-(1)
2y=6
所以y=3
x=(27-5y)/2=6
x=6,y=3
由条件可得方程组:2x+3y=21 (1)
2x+5y=27 (2)
解之得:x=6;y=3
x+x+y+y+y+y+y=27 相减x+x+y+y+y=21
y+y=6 y=3 x=6
x+x+y+y+y=21 ,x+x+y+y+y+y+y=27 ,x ,y=?
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