若3^x=4,3^y=6,求9^2x-y+27^x-y

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若3^x=4,3^y=6,求9^2x-y+27^x-y
若3^x=4,3^y=6,求9^2x-y+27^x-y

若3^x=4,3^y=6,求9^2x-y+27^x-y
9^（2x-y）+27^（x-y）=3^4x÷3^2y+3^3x÷3^3y
=(3^x)^4÷(3^y)^2+(3^x)^3÷(3^y)^3
=4^4÷6^2+(4^3)÷(6^3)=200/27

4^4*6^(-2)*(4+1/6)

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