已知sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,求sinθ与cos2θ的值!具体过程,限今晚.谢谢!
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![已知sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,求sinθ与cos2θ的值!具体过程,限今晚.谢谢!](/uploads/image/z/3995901-45-1.jpg?t=%E5%B7%B2%E7%9F%A5sin%28%CF%80%EF%BC%8F6%EF%BC%8D%CE%B8%EF%BC%89%3D%EF%B9%A33%EF%BC%8F5%2C%CF%80%EF%BC%8F6%EF%BC%9C%CE%B8%EF%BC%9C2%CF%80%EF%BC%8F3%2C%E6%B1%82sin%CE%B8%E4%B8%8Ecos2%CE%B8%E7%9A%84%E5%80%BC%21%E5%85%B7%E4%BD%93%E8%BF%87%E7%A8%8B%2C%E9%99%90%E4%BB%8A%E6%99%9A.%E8%B0%A2%E8%B0%A2%21)
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已知sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,求sinθ与cos2θ的值!具体过程,限今晚.谢谢!
已知sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,求sinθ与cos2θ的值!具体过程,限今晚.谢谢!
已知sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,求sinθ与cos2θ的值!具体过程,限今晚.谢谢!
sin(π/6-θ)=﹣3/5,π/6<θ<2π/3,
则cos(π/6-θ)=4/5,
sinθ=sin[π/6 -(π/6-θ)]
= sinπ/6cos(π/6-θ)- cosπ/6 sin(π/6-θ)
=(4+3√3)/10.
cos2θ=1-2 sin²θ=(7-24√3)/50.
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