f(x+1/x)=x3+1/x3(是3次方)求f(x)f(x+1/x)=x3+1/x3=(x+1/x)(x²-1+1/x²)①=(x+1/x)[(x+1/x)²-3]②∴f(x)=x(x²-3)③请问2是怎么得到3的,
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![f(x+1/x)=x3+1/x3(是3次方)求f(x)f(x+1/x)=x3+1/x3=(x+1/x)(x²-1+1/x²)①=(x+1/x)[(x+1/x)²-3]②∴f(x)=x(x²-3)③请问2是怎么得到3的,](/uploads/image/z/3997809-9-9.jpg?t=f%28x%EF%BC%8B1%2Fx%EF%BC%89%EF%BC%9Dx3%2B1%2Fx3%EF%BC%88%E6%98%AF3%E6%AC%A1%E6%96%B9%EF%BC%89%E6%B1%82f%28x%29f%28x%EF%BC%8B1%2Fx%EF%BC%89%EF%BC%9Dx3%2B1%2Fx3%3D%28x%2B1%2Fx%EF%BC%89%EF%BC%88x%26%23178%3B-1%2B1%2Fx%26%23178%3B%EF%BC%89%E2%91%A0%EF%BC%9D%28x%2B1%2Fx%29%5B%EF%BC%88x%2B1%2Fx%29%26%23178%3B-3%5D%E2%91%A1%E2%88%B4f%28x%29%3Dx%28x%26%23178%3B-3%29%E2%91%A2%E8%AF%B7%E9%97%AE2%E6%98%AF%E6%80%8E%E4%B9%88%E5%BE%97%E5%88%B03%E7%9A%84%2C)
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