1.求函数y=3sin(x/6-7π/12)的单调递增区间.2.化简{[tan(π-x)]/[sin(π-α)*sin(3π/2-α)]}+{[sin(2π-α)*cos(α-3π/2)]/[sin(3π/2+α)*cos(2π-α)]}.

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1.求函数y=3sin(x/6-7π/12)的单调递增区间.2.化简{[tan(π-x)]/[sin(π-α)*sin(3π/2-α)]}+{[sin(2π-α)*cos(α-3π/2)]/[sin(3π/2+α)*cos(2π-α)]}.
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1.求函数y=3sin(x/6-7π/12)的单调递增区间.2.化简{[tan(π-x)]/[sin(π-α)*sin(3π/2-α)]}+{[sin(2π-α)*cos(α-3π/2)]/[sin(3π/2+α)*cos(2π-α)]}.
1.求函数y=3sin(x/6-7π/12)的单调递增区间.
2.化简{[tan(π-x)]/[sin(π-α)*sin(3π/2-α)]}+{[sin(2π-α)*cos(α-3π/2)]/[sin(3π/2+α)*cos(2π-α)]}.

1.求函数y=3sin(x/6-7π/12)的单调递增区间.2.化简{[tan(π-x)]/[sin(π-α)*sin(3π/2-α)]}+{[sin(2π-α)*cos(α-3π/2)]/[sin(3π/2+α)*cos(2π-α)]}.

应该是没问题的~

回答这是对的
被抢先了
你可以放心看

(1)正弦函数的单调增区间为：(2kπ-π/2，2kπ+π/2)
2kπ-π/2(2)利用诱导公式(奇变偶不变，符号看象限)
原式=-tanx/(sinαcosα)-sinαsinα/cosαcosα=-tanx/(sinαcosα)-(tanα)^2=-2tanx/sin2α-(tanα)^2

我认为我的对

(1)正弦函数的单调增区间为：(2kπ-π/2，2kπ+π/2)
2kπ-π/2(2)利用诱导公式(奇变偶不变，符号看象限)
原式=-tanx/(sinαcosα)-sinαsinα/cosαcosα=-tanx/(sinαcosα)-(tanα)^2=-2tanx/sin2α-(tanα)^2

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