在正方体ABCD-A1B1CID1中,M为CC1中点,AC交BD于点O,求证A1O垂直与平面MBD因为OM与A1O同在面A1ACC1内,而且A1A:AO=OC:CM,所以A1O⊥OM.于是,可以说明A1O⊥平面MBD。为什么A1A:AO=OC:CM,A1O就垂直OM?
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![在正方体ABCD-A1B1CID1中,M为CC1中点,AC交BD于点O,求证A1O垂直与平面MBD因为OM与A1O同在面A1ACC1内,而且A1A:AO=OC:CM,所以A1O⊥OM.于是,可以说明A1O⊥平面MBD。为什么A1A:AO=OC:CM,A1O就垂直OM?](/uploads/image/z/4043289-57-9.jpg?t=%E5%9C%A8%E6%AD%A3%E6%96%B9%E4%BD%93ABCD-A1B1CID1%E4%B8%AD%2CM%E4%B8%BACC1%E4%B8%AD%E7%82%B9%2CAC%E4%BA%A4BD%E4%BA%8E%E7%82%B9O%2C%E6%B1%82%E8%AF%81A1O%E5%9E%82%E7%9B%B4%E4%B8%8E%E5%B9%B3%E9%9D%A2MBD%E5%9B%A0%E4%B8%BAOM%E4%B8%8EA1O%E5%90%8C%E5%9C%A8%E9%9D%A2A1ACC1%E5%86%85%EF%BC%8C%E8%80%8C%E4%B8%94A1A%3AAO%3DOC%3ACM%2C%E6%89%80%E4%BB%A5A1O%E2%8A%A5OM.%E4%BA%8E%E6%98%AF%EF%BC%8C%E5%8F%AF%E4%BB%A5%E8%AF%B4%E6%98%8EA1O%E2%8A%A5%E5%B9%B3%E9%9D%A2MBD%E3%80%82%E4%B8%BA%E4%BB%80%E4%B9%88A1A%3AAO%3DOC%3ACM%EF%BC%8CA1O%E5%B0%B1%E5%9E%82%E7%9B%B4OM%EF%BC%9F)
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