如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证①EC=BF②EC⊥BF.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 04:41:34
xj0F_%tc5vμFнb͌O)tf" $نvS30IlB!d%>蜼_ߞpk⦜ݔq9j\N**~rZjZ&$ǓeWsڽ"zҢA("Q{Fhqc"mUBQV,R
,-dQJ%٨d28rK^`mmle\dQ29W)
'%3̂Сw ,
)3,?-ey҂88pᣳ7ejK!A_D4Y
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证①EC=BF②EC⊥BF.
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证①EC=BF②EC⊥BF.
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证①EC=BF②EC⊥BF.
如图所示,已知ae⊥ab,af⊥ac,ae=ab,af=ac.求证ec⊥bf
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证:(1)EC=BF;(2)EC⊥BF.
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证①EC=BF②EC⊥BF.
如图所示,已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证:(1)EC=BF;(2)EC⊥BF
如图所示,已知AB=AC,AE=AF,AE⊥Ec,AF⊥BF,垂足点为E、F求证:∠1=∠2
如图所示,已知AE⊥AB,AF⊥AC,AF=AC,求证:(1)EC=BF(2)EC⊥BF
如图所示,已知AE垂直AB,AF垂直AC,AE=AB,AF=AC,求证.EC垂直BF
如图所示,已知三角形ABC中,AB=AC,F在AC上,在BA的延长线上取AE=AF,求证:EF⊥BC.
如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF
已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.试证明:(1)EC=BF;(2)EC⊥BF
已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.试证明:(1)EC=BF;(2)EC⊥BF
已知AE⊥AB,AF⊥AC,AE=AB,AF=AC.求证EC=BF,EC⊥BF快
如图8,已知:AE⊥AB,AF⊥AC,AE=AB,AF=AC.试证明:(1)CE=BF;(2)CE⊥BF
已知AD是△ABC的中线AE⊥AB,AF⊥AC且AE=AB,AF=AC连接EF求证AD=1/2EF
已知AD是△ABC的中线AE⊥AB,AF⊥AC且AE=AB,AF=AC连接EF求证AD=1/2EF
如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:BE=DC
如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:BE=DC非常急
如图,已知AE⊥AD,AF⊥AB,AF=AB,AE=AD=BC,AD‖BC,求证AC⊥EF