一质点沿X轴作简谐运动,振动方程为X=4cos(2πt+1/3π)从t=0时刻起,到质点位置在x=-2处,且向X轴正方一质点沿X轴作简谐运动,振动方程为X=4cos(2πt+1/3π)从t=0时刻起,到质点位置在x=-2处,且向X轴
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 12:56:47
![一质点沿X轴作简谐运动,振动方程为X=4cos(2πt+1/3π)从t=0时刻起,到质点位置在x=-2处,且向X轴正方一质点沿X轴作简谐运动,振动方程为X=4cos(2πt+1/3π)从t=0时刻起,到质点位置在x=-2处,且向X轴](/uploads/image/z/4057133-5-3.jpg?t=%E4%B8%80%E8%B4%A8%E7%82%B9%E6%B2%BFX%E8%BD%B4%E4%BD%9C%E7%AE%80%E8%B0%90%E8%BF%90%E5%8A%A8%2C%E6%8C%AF%E5%8A%A8%E6%96%B9%E7%A8%8B%E4%B8%BAX%3D4cos%EF%BC%882%CF%80t%2B1%2F3%CF%80%EF%BC%89%E4%BB%8Et%3D0%E6%97%B6%E5%88%BB%E8%B5%B7%2C%E5%88%B0%E8%B4%A8%E7%82%B9%E4%BD%8D%E7%BD%AE%E5%9C%A8x%3D-2%E5%A4%84%2C%E4%B8%94%E5%90%91X%E8%BD%B4%E6%AD%A3%E6%96%B9%E4%B8%80%E8%B4%A8%E7%82%B9%E6%B2%BFX%E8%BD%B4%E4%BD%9C%E7%AE%80%E8%B0%90%E8%BF%90%E5%8A%A8%2C%E6%8C%AF%E5%8A%A8%E6%96%B9%E7%A8%8B%E4%B8%BAX%3D4cos%EF%BC%882%CF%80t%2B1%2F3%CF%80%EF%BC%89%E4%BB%8Et%3D0%E6%97%B6%E5%88%BB%E8%B5%B7%2C%E5%88%B0%E8%B4%A8%E7%82%B9%E4%BD%8D%E7%BD%AE%E5%9C%A8x%3D-2%E5%A4%84%2C%E4%B8%94%E5%90%91X%E8%BD%B4)
x]oPƿB+sziB?WYL1ZGؗi_֗x¤iGr~z^l7'E~mH?$i%{9K|쥳UWR|K({|@]DNwҞ$Fdf/xοA";~ zTGk=nHNd c'[p8-%wI%n