已知数列an满足a1=0 a2=2 且对任意m、n∈N* 都有a2m-1+a2n-1=2(am+n-1)+2(m-n)^21)求a3 a52)设bn =a2n+1-(a2n-1)(n∈N*),证明bn是等差数列.m+n-1 2m-1 2m+1 2n-1 2n+1 是脚码
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![已知数列an满足a1=0 a2=2 且对任意m、n∈N* 都有a2m-1+a2n-1=2(am+n-1)+2(m-n)^21)求a3 a52)设bn =a2n+1-(a2n-1)(n∈N*),证明bn是等差数列.m+n-1 2m-1 2m+1 2n-1 2n+1 是脚码](/uploads/image/z/4096512-0-2.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E6%BB%A1%E8%B6%B3a1%3D0+a2%3D2+%E4%B8%94%E5%AF%B9%E4%BB%BB%E6%84%8Fm%E3%80%81n%E2%88%88N%2A+%E9%83%BD%E6%9C%89a2m-1%2Ba2n-1%3D2%EF%BC%88am%2Bn-1%29%2B2%28m-n%29%5E21%EF%BC%89%E6%B1%82a3+a52%EF%BC%89%E8%AE%BEbn+%3Da2n%2B1-%28a2n-1%29%28n%E2%88%88N%2A%29%2C%E8%AF%81%E6%98%8Ebn%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97.m%2Bn-1+2m-1+2m%2B1+2n-1+2n%2B1+%E6%98%AF%E8%84%9A%E7%A0%81)
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