如图,在△CDE中,∠DCE=90°,CD=CE,DA⊥AB于A,EB⊥AB于B,试说明AB=AD+BE图:
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![如图,在△CDE中,∠DCE=90°,CD=CE,DA⊥AB于A,EB⊥AB于B,试说明AB=AD+BE图:](/uploads/image/z/4297530-66-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3CDE%E4%B8%AD%2C%E2%88%A0DCE%3D90%C2%B0%2CCD%3DCE%2CDA%E2%8A%A5AB%E4%BA%8EA%2CEB%E2%8A%A5AB%E4%BA%8EB%2C%E8%AF%95%E8%AF%B4%E6%98%8EAB%3DAD%2BBE%E5%9B%BE%EF%BC%9A)
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