C语言的题有4个圆塔,圆心分别为:(2,2,(-2,2),(-2,-2),(2,-2),圆半径为1.这4个塔的高度为10m,塔以外无建筑物.今输入任一点的坐标,求该点的建筑高度(塔外的高度为0).# include main(){int x,y
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![C语言的题有4个圆塔,圆心分别为:(2,2,(-2,2),(-2,-2),(2,-2),圆半径为1.这4个塔的高度为10m,塔以外无建筑物.今输入任一点的坐标,求该点的建筑高度(塔外的高度为0).# include main(){int x,y](/uploads/image/z/4314411-27-1.jpg?t=C%E8%AF%AD%E8%A8%80%E7%9A%84%E9%A2%98%E6%9C%894%E4%B8%AA%E5%9C%86%E5%A1%94%2C%E5%9C%86%E5%BF%83%E5%88%86%E5%88%AB%E4%B8%BA%EF%BC%9A%EF%BC%882%2C2%2C%EF%BC%88-2%2C2%EF%BC%89%2C%EF%BC%88-2%2C-2%EF%BC%89%2C%EF%BC%882%2C-2%EF%BC%89%2C%E5%9C%86%E5%8D%8A%E5%BE%84%E4%B8%BA1.%E8%BF%994%E4%B8%AA%E5%A1%94%E7%9A%84%E9%AB%98%E5%BA%A6%E4%B8%BA10m%2C%E5%A1%94%E4%BB%A5%E5%A4%96%E6%97%A0%E5%BB%BA%E7%AD%91%E7%89%A9.%E4%BB%8A%E8%BE%93%E5%85%A5%E4%BB%BB%E4%B8%80%E7%82%B9%E7%9A%84%E5%9D%90%E6%A0%87%2C%E6%B1%82%E8%AF%A5%E7%82%B9%E7%9A%84%E5%BB%BA%E7%AD%91%E9%AB%98%E5%BA%A6%EF%BC%88%E5%A1%94%E5%A4%96%E7%9A%84%E9%AB%98%E5%BA%A6%E4%B8%BA0%EF%BC%89.%23+include+main%28%29%7Bint+x%2Cy)
C语言的题有4个圆塔,圆心分别为:(2,2,(-2,2),(-2,-2),(2,-2),圆半径为1.这4个塔的高度为10m,塔以外无建筑物.今输入任一点的坐标,求该点的建筑高度(塔外的高度为0).# include main(){int x,y
C语言的题
有4个圆塔,圆心分别为:(2,2,(-2,2),(-2,-2),(2,-2),圆半径为1.这4个塔的高度为10m,塔以外无建筑物.今输入任一点的坐标,求该点的建筑高度(塔外的高度为0).
# include
main()
{
int x,y,s1,s2,s3,s4,h;
scanf("%d%d",&x,&y);
(x-2)*(x-2)+(y-2)*(y-2)=s1;
(x-2)*(x-2)+(y+2)*(y+2)=s2;
(x+2)*(x+2)+(y-2)*(y-2)=s3;
(x+2)*(x+2)+(y+2)*(y+2)=s4;
if
s1
C语言的题有4个圆塔,圆心分别为:(2,2,(-2,2),(-2,-2),(2,-2),圆半径为1.这4个塔的高度为10m,塔以外无建筑物.今输入任一点的坐标,求该点的建筑高度(塔外的高度为0).# include main(){int x,y
塔是什么形状呢?如果是圆锥就是这样吧.
# include
# include
main()
{
double s1,s2,s3,s4,h=0;
float x,y;
scanf("%f%f",&x,&y);
s1=(x-2)*(x-2)+(y-2)*(y-2);
s2=(x-2)*(x-2)+(y+2)*(y+2);
s3=(x+2)*(x+2)+(y-2)*(y-2);
s4=(x+2)*(x+2)+(y+2)*(y+2);
if(s1