已知x,y满足(x-y-1)(x+y)≤0则(x+1)^2+(y+1)^2的最小值是多少(是平面区域的题)

已知x,y满足y 已知x,y满足{x>=1,x+y 已知x,y满足{x>=1,x+y 已知实数x,y满足x-y 已知实数X,Y满足{|x+y| 已知变量x,y满足x大于等于1,y 已知x,y满足约束条件：x-y+1>=0,x+y-2>=0,x 已知实数x,y满足：y 已知实数x,y满足约束条件x+y>3,y 感激不尽1.x,y满足(x-y-1)(x+y) 已知x.y满足(x-y-2≤0,x 2y-5≥0,y-2≤0 则3x+y/x+1得多少 已知实数x,y满足不等式组x≥0,y≥0,x+y≤1,则x^2+y^2-2x-2y的最小值 已知实数x,y满足,X-2y≥-4,3x-2y≤12,x+y≥2,则y/(x+1)的取值范围 已知实数x、y满足-1 已知实数x,y满足：1 已知变量x,y满足约束条件1 已知x,y满足约束条件1 已知实数x,y满足方程x*x+y*y-4x+1=0.求y-x的最大值