一道数学化简 题

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一道数学化简 题
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一道数学化简 题
一道数学化简 题

一道数学化简 题
原式=﹙x²-xy+xy+y²﹚/﹙x²-y²﹚-2xy/﹙x²-y²﹚
=﹙x²+y²-2xy﹚/﹙x²-y²﹚
=﹙x-y﹚²/﹙x-y﹚﹙x+y﹚
=﹙x-y﹚/﹙x+y﹚.

(x-y)\(x+y)
别光问啊 该采纳的采纳啊!

原式=x(x-y)/(x+y)(x-y)+y(x+y)/(x+y)(x-y)-2xy/(x+y)(x-y)
=(x^2-xy+xy+y^2-2xy)/(x+y)(x-y)
=(x^2-2xy+y^2)/(x+y)(x-y)
=(x-y)^2/(x+y)(x-y)
...

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原式=x(x-y)/(x+y)(x-y)+y(x+y)/(x+y)(x-y)-2xy/(x+y)(x-y)
=(x^2-xy+xy+y^2-2xy)/(x+y)(x-y)
=(x^2-2xy+y^2)/(x+y)(x-y)
=(x-y)^2/(x+y)(x-y)
=(x-y)/(x+y)

您好,很高兴为您答疑解惑
如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢。
祝学习进步

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