作业帮一道数学化简 题
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一道数学化简 题
一道数学化简 题
一道数学化简 题
原式＝﹙x²－xy＋xy＋y²﹚/﹙x²－y²﹚－2xy/﹙x²－y²﹚
＝﹙x²＋y²－2xy﹚/﹙x²－y²﹚
＝﹙x－y﹚²/﹙x－y﹚﹙x＋y﹚
＝﹙x－y﹚/﹙x＋y﹚.
(x-y)\(x+y)
别光问啊 该采纳的采纳啊！
原式=x(x-y)/(x+y)(x-y)+y(x+y)/(x+y)(x-y)-2xy/(x+y)(x-y)
=(x^2-xy+xy+y^2-2xy)/(x+y)(x-y)
=(x^2-2xy+y^2)/(x+y)(x-y)
=(x-y)^2/(x+y)(x-y)
...
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原式=x(x-y)/(x+y)(x-y)+y(x+y)/(x+y)(x-y)-2xy/(x+y)(x-y)
=(x^2-xy+xy+y^2-2xy)/(x+y)(x-y)
=(x^2-2xy+y^2)/(x+y)(x-y)
=(x-y)^2/(x+y)(x-y)
=(x-y)/(x+y)
您好，很高兴为您答疑解惑
如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
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