已知 2x-y=10,求【（x^2+y^2(-(x-y)^2+2y(x-y)】除以y的值

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已知 2x-y=10,求【（x^2+y^2(-(x-y)^2+2y(x-y)】除以y的值
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已知 2x-y=10,求【（x^2+y^2(-(x-y)^2+2y(x-y)】除以y的值
已知 2x-y=10,求【（x^2+y^2(-(x-y)^2+2y(x-y)】除以y的值

已知 2x-y=10,求【（x^2+y^2(-(x-y)^2+2y(x-y)】除以y的值
[(x^2+y^2)-(x-y)^2+2y(x-y)]/y
=[(x^2+y^2)-(x^2-2xy+y^2)+2xy-2y^2]/y
=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/y
=(4xy-2y^2)/y
=2y(2x-y)/y
=2(2x-y)
=2×10
=20

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