1/a+1/b=4,求4a+3ab+4b/-3a+2ab-3b

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1/a+1/b=4,求4a+3ab+4b/-3a+2ab-3b
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1/a+1/b=4,求4a+3ab+4b/-3a+2ab-3b
1/a+1/b=4,求4a+3ab+4b/-3a+2ab-3b

1/a+1/b=4,求4a+3ab+4b/-3a+2ab-3b
1/a+1/b=(a+b)/ab=4
a+b=4ab
原式=[4(a+b)+3ab]/[-3(a+b)+2an]
=[4(4ab)+3ab]/[-3(4ab)+2ab]
=19ab/(-10ab)
=-19/10

1/a+1/b=4
通分下得 a+b=4ab
代人右边得
(4*4ab+3ab)/(-3*4ab+2ab)=-19/10