X+2Y-5=0 2Y+3Z-13=0 3Z+X-10=0 怎么解
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X+2Y-5=0 2Y+3Z-13=0 3Z+X-10=0 怎么解
X+2Y-5=0 2Y+3Z-13=0 3Z+X-10=0 怎么解
X+2Y-5=0 2Y+3Z-13=0 3Z+X-10=0 怎么解
x+2y-5=0, ① 2y+3z-13=0, ② 3z+x-10=0. ③ ②-③,得:2y+3z-13-3z-x+10=0 2y-x-3=0, 此式与①相加,得:2y-x-3+x+2y-5=0 4y-8=0 4y=8 y=2; 把y=2代入①,得:x+2(2)-5=0 x+4-5=0 x-1=0 x=1; 把x=1代入③,得:3z+1-10=0 3z-9=0 3z=9 z=3. 所以,x=1, y=2, z=3.
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
三元一次方程:x+y-z=0 x+2y+z=13 2x-3y+2z=5x+y-z=0 x+2y+z=13 2x-3y+2z=5
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
5x+4y+z=0 3x+y-4z=13 x+y+z=—2
三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
已知z、y、z同时满足x+3y-5z=0,2x-y-3z=0,求x:y:z
六年级三元一次方程组.解下列方程组:(1)5x-3y+z=25x+2y-4z=3-5x+y-z=2(2)x-y-z=-13x_5y+7z=114x-y+2z=-1(3)9x-5y+z=-69x+y+4z=3-9x+3y-5z=0(4)x+y=22x+z=-27y+z=13
解三元一次方程,①{x+y-z=0{ x+2y+z=13{2x-3y+2z=5②{x+y-z=11{y+z-x=5{z+x-y=1③{x+y=1{y+z=6{z+x=3
4.{x+y-z=0 5.{x+y-z=11 6.{x+y=1x+2y+z=13 y+z-x=5 y+z=62x-3y+2z=5 z+x-y=1 z+x=3
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
x+y-z=0 x+2y-z=3 2x-3y+2z=5
x+y-z=0 2x-3y+2z=5 x+2y-z=3
已知{x-5y+2z=0 3x-5y-4z=0,求x:y:z
x+y+z=0,3x-2y-2z=5,y-z=2x-7