数列满足a1=1,an+1=2n+1 (n属于正整数集)1)、求证数列{an+1}是等比数列; 2)、求{an}的通项公式.正确的是:数列满足a1=1,an+1=2an+1 (n属于正整数集)
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![数列满足a1=1,an+1=2n+1 (n属于正整数集)1)、求证数列{an+1}是等比数列; 2)、求{an}的通项公式.正确的是:数列满足a1=1,an+1=2an+1 (n属于正整数集)](/uploads/image/z/4553975-47-5.jpg?t=%E6%95%B0%E5%88%97%E6%BB%A1%E8%B6%B3a1%3D1%2Can%2B1%3D2n%2B1+%EF%BC%88n%E5%B1%9E%E4%BA%8E%E6%AD%A3%E6%95%B4%E6%95%B0%E9%9B%86%EF%BC%891%EF%BC%89%E3%80%81%E6%B1%82%E8%AF%81%E6%95%B0%E5%88%97%7Ban%2B1%7D%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%EF%BC%9B+2%EF%BC%89%E3%80%81%E6%B1%82%EF%BD%9Ban%EF%BD%9D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F.%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AF%EF%BC%9A%E6%95%B0%E5%88%97%E6%BB%A1%E8%B6%B3a1%3D1%EF%BC%8Can%2B1%3D2an%2B1+%EF%BC%88n%E5%B1%9E%E4%BA%8E%E6%AD%A3%E6%95%B4%E6%95%B0%E9%9B%86%EF%BC%89)
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数列满足a1=1,an+1=2n+1 (n属于正整数集)1)、求证数列{an+1}是等比数列; 2)、求{an}的通项公式.正确的是:数列满足a1=1,an+1=2an+1 (n属于正整数集)
数列满足a1=1,an+1=2n+1 (n属于正整数集)
1)、求证数列{an+1}是等比数列; 2)、求{an}的通项公式.
正确的是:数列满足a1=1,an+1=2an+1 (n属于正整数集)
数列满足a1=1,an+1=2n+1 (n属于正整数集)1)、求证数列{an+1}是等比数列; 2)、求{an}的通项公式.正确的是:数列满足a1=1,an+1=2an+1 (n属于正整数集)
同学,题目错了吧
a(n+1)=2an +1
解 :a1+1=2≠0
[a(n+1)+1]/[a(n)+1]
=[2a(n)+1+1]/[a(n)+1]
=2
所以 {a(n)+1}是等比数列,公比,首项,均为2
所以 a(n)+1=2*2^(n-1)=2^n
a(n)=2^n -1
s是 a(n+1)=2an+1
则a(n+1)+1=2an+2=2(an+1)
所以[a(n+1)+1]/(an+1)=2
所以an+1是等比数列
[a(n+1)+1]/(an+1)=2
所以q=2
则an+1=(a1+1)*q^(n-1)=2^n
所以an=-1+2^n
buzhidao
题目应该是这样的吧
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