作业帮AB=DC,AE=DF,CE=FB,求证AF=DE
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AB=DC,AE=DF,CE=FB,求证AF=DE
AB=DC,AE=DF,CE=FB,求证AF=DE
AB=DC,AE=DF,CE=FB,求证AF=DE
因为AB=DC
AE=DF,
CE=FB
CE+EF=EF+FB
所以三角形ABE=三角形CDF
因为 角DCB=角ABF
AB=DC BF=CE
三角形ABF=三角形CDE
所以AF=DE
已知:如图,AB=DC,AE=DF,CE=FB,求证:AF=DE
已知如图AB=DC,AE=DF,CE=FB求证AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证：AF=DE
AB=DC,AE=DF,CE=FB,求证AF=DE行了
AB=DC,AE=DF,CE=FB,求证AF=DE
如图:AB=CD,AE=DF,CE=FB.求证:AE∥DF
如图,ab=cd,ae=df,ce=fb,求证af=de
如图,已知AB等于DC,AE等于DF,CE等于FB,求证AF等于DE
如下图,AB=DC,BF=CE,AE=DF,求证AB//CD
如图,已知AB=DC AE=DF .CE=BF 求证:AF=DE
AB=DC.AE=DF.CE=BF.求证：AF=DE.
如图,已知AB=DC,AE=DF,CE=BF,求证：AF=DE
已知:如图,AD=CD CE=BF DF=AE 求证AB‖DC
如图,点ABCD在同一条直线上,EA⊥AD,FD⊥AD,AE=DF,AB=DC,求证：EC=FB.如图：
如图所示,AB=CD,AE=DF,CE=BF,求证 AE‖DF
如图,AB=CD,AE=DF,CE=BF,求证AE平行DF
如图,AB=CD,AE=DF,CE=BF,求证：AE平行DF