coS(A+B)=0.2,cos(A-B)=0.6
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 16:48:33
![coS(A+B)=0.2,cos(A-B)=0.6](/uploads/image/z/465557-5-7.jpg?t=coS%EF%BC%88A%2BB%EF%BC%89%3D0.2%2Ccos%28A-B%EF%BC%89%3D0.6)
x)K~QN[=#b
G](&HS
TE~
q9k UhZ@I7QH8Pb˦OvvU MtPR +{3)35T )@|-۞N{wݳE:@cѓY|gS7yv>_ѭ ϧxovXXF 1 ҇O
coS(A+B)=0.2,cos(A-B)=0.6
coS(A+B)=0.2,
cos(A-B)=0.6
coS(A+B)=0.2,cos(A-B)=0.6
COS(A+B)=COSA*COSB-SINA*SINB=0.2
COS(A+B)=COSA*COSB+SINA*SINB=0.6
那么COSA*COSB=0.4,SINA*SINB=0.2
又SINA^2+COSA^2=1 SINB^2+COSB^2=1
然后置换,换成2个未知数,2个方程,再运用微积分解.
求证a cos A + b cos B = c cos (A-B )
COS^2A+COS^2B=2cos(A+B)*cos(A-B)什么公式?
coS(A+B)=0.2,cos(A-B)=0.6
证明:cos(a+b)*cos(a-b)=cos2b-cos2a
cos^2(a+b)=?
求证cos(a+b)cos(a-b)=cos^2b-sin^2a
求证cos(a+b)cos(a-b)=cos^2a-sin^2b
求证:cos(a+b)cos(a-b)=cos平方b-sin平方a
求证:cos²a-sin²b=cos(a-b)cos(a+b)
cosC=cos(A+B)为什么?
cos(A+B)=-COSC对不对
(1)cos(-a+b)=-cos(a-b)!(2)cos(-a-b)=cos(a+b)哪个对?
COS(a-B)公式
证明cos(A+B)
求证cos(a+b)cos(a-b)=cos平方a-sinb
若COS(A+B)COS(A-B)=1/3,则COS^2A-COS^2B=多少
如何证明cos a +cos b =2*(cos(a+b)/2)*(cos(a-b)/2) 速度
若cos(A+B)cos(A-B)=1/3 则cos平方A+cos平方B 等于