将0.2mol某烷烃完全燃烧后,生成的气体缓慢通过盛有0.5L浓度为2mol/L的NaOH溶液后面的我懂了,只是前面,NaOH都反应了?WHY?怎么判断的?nNa2CO3+3nNaHCO3=1mol?根据物料守恒来做 首先Na离子守恒nNa2CO3+3nNaHCO
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 12:26:50
![将0.2mol某烷烃完全燃烧后,生成的气体缓慢通过盛有0.5L浓度为2mol/L的NaOH溶液后面的我懂了,只是前面,NaOH都反应了?WHY?怎么判断的?nNa2CO3+3nNaHCO3=1mol?根据物料守恒来做 首先Na离子守恒nNa2CO3+3nNaHCO](/uploads/image/z/4877279-71-9.jpg?t=%E5%B0%860.2mol%E6%9F%90%E7%83%B7%E7%83%83%E5%AE%8C%E5%85%A8%E7%87%83%E7%83%A7%E5%90%8E%2C%E7%94%9F%E6%88%90%E7%9A%84%E6%B0%94%E4%BD%93%E7%BC%93%E6%85%A2%E9%80%9A%E8%BF%87%E7%9B%9B%E6%9C%890.5L%E6%B5%93%E5%BA%A6%E4%B8%BA2mol%2FL%E7%9A%84NaOH%E6%BA%B6%E6%B6%B2%E5%90%8E%E9%9D%A2%E7%9A%84%E6%88%91%E6%87%82%E4%BA%86%2C%E5%8F%AA%E6%98%AF%E5%89%8D%E9%9D%A2%2CNaOH%E9%83%BD%E5%8F%8D%E5%BA%94%E4%BA%86%3FWHY%3F%E6%80%8E%E4%B9%88%E5%88%A4%E6%96%AD%E7%9A%84%3FnNa2CO3%2B3nNaHCO3%3D1mol%3F%E6%A0%B9%E6%8D%AE%E7%89%A9%E6%96%99%E5%AE%88%E6%81%92%E6%9D%A5%E5%81%9A+%E9%A6%96%E5%85%88Na%E7%A6%BB%E5%AD%90%E5%AE%88%E6%81%92nNa2CO3%2B3nNaHCO)
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