已知x,y满足√4x-5y+√x-y-1=0,则√xy-√x/y的值为多少?结果为什么x=5,y=4?什么道理?
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![已知x,y满足√4x-5y+√x-y-1=0,则√xy-√x/y的值为多少?结果为什么x=5,y=4?什么道理?](/uploads/image/z/4950064-64-4.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%E6%BB%A1%E8%B6%B3%E2%88%9A4x-5y%2B%E2%88%9Ax-y-1%3D0%2C%E5%88%99%E2%88%9Axy-%E2%88%9Ax%2Fy%E7%9A%84%E5%80%BC%E4%B8%BA%E5%A4%9A%E5%B0%91%3F%E7%BB%93%E6%9E%9C%E4%B8%BA%E4%BB%80%E4%B9%88x%3D5%2Cy%3D4%3F%E4%BB%80%E4%B9%88%E9%81%93%E7%90%86%3F)
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已知x,y满足√4x-5y+√x-y-1=0,则√xy-√x/y的值为多少?结果为什么x=5,y=4?什么道理?
已知x,y满足√4x-5y+√x-y-1=0,则√xy-√x/y的值为多少?结果为什么x=5,y=4?什么道理?
已知x,y满足√4x-5y+√x-y-1=0,则√xy-√x/y的值为多少?结果为什么x=5,y=4?什么道理?
由题意可知:4x-5y≥0且x-y-1≥0
则要使√(4x-5y)+√(x-y-1)=0成立
须使:4x-5y=0 (1)
且x-y-1=0即x=y+1 (2)
将(2)代入(1)式得:
4y+4-5y=0
解得y=4,x=5
就是这样!
可知:4x-5y≥0且x-y-1≥0
则要使√(4x-5y)+√(x-y-1)=0成立
须使:4x-5y=0 (1)
且x-y-1=0即x=y+1 (2)
将(2)代入(1)式得:
4y+4-5y=0
解得y=4,x=5
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