答案已给出,已知Rt△ABC和Rt△BCD相似,∠ABC=∠CDB=90°,且AC=a,BC1、已知Rt△ABC和Rt△BCD相似,∠ABC=∠CDB=90°,且AC=a,BC=b,则BD=___b²/a或b²√(a²-b²)/a_____.(用含a,b的代数式表
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![答案已给出,已知Rt△ABC和Rt△BCD相似,∠ABC=∠CDB=90°,且AC=a,BC1、已知Rt△ABC和Rt△BCD相似,∠ABC=∠CDB=90°,且AC=a,BC=b,则BD=___b²/a或b²√(a²-b²)/a_____.(用含a,b的代数式表](/uploads/image/z/4952398-22-8.jpg?t=%E7%AD%94%E6%A1%88%E5%B7%B2%E7%BB%99%E5%87%BA%2C%E5%B7%B2%E7%9F%A5Rt%E2%96%B3ABC%E5%92%8CRt%E2%96%B3BCD%E7%9B%B8%E4%BC%BC%2C%E2%88%A0ABC%EF%BC%9D%E2%88%A0CDB%EF%BC%9D90%C2%B0%2C%E4%B8%94AC%EF%BC%9Da%2CBC1%E3%80%81%E5%B7%B2%E7%9F%A5Rt%E2%96%B3ABC%E5%92%8CRt%E2%96%B3BCD%E7%9B%B8%E4%BC%BC%2C%E2%88%A0ABC%EF%BC%9D%E2%88%A0CDB%EF%BC%9D90%C2%B0%2C%E4%B8%94AC%EF%BC%9Da%2CBC%EF%BC%9Db%2C%E5%88%99BD%EF%BC%9D___b%26%23178%3B%2Fa%E6%88%96b%26%23178%3B%E2%88%9A%EF%BC%88a%26%23178%3B-b%26%23178%3B%29%2Fa_____%EF%BC%8E%EF%BC%88%E7%94%A8%E5%90%ABa%2Cb%E7%9A%84%E4%BB%A3%E6%95%B0%E5%BC%8F%E8%A1%A8)
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