已知A,B,C为三角形ABC的生三个内角且向量m=(1,cosC/2),向量n=(根号3sinC/2+cosC/2,3/2)共线.1.求角C2.满足2acosC+c=2b,试判断三角形的形状.
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![已知A,B,C为三角形ABC的生三个内角且向量m=(1,cosC/2),向量n=(根号3sinC/2+cosC/2,3/2)共线.1.求角C2.满足2acosC+c=2b,试判断三角形的形状.](/uploads/image/z/5166509-5-9.jpg?t=%E5%B7%B2%E7%9F%A5A%2CB%2CC%E4%B8%BA%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E7%94%9F%E4%B8%89%E4%B8%AA%E5%86%85%E8%A7%92%E4%B8%94%E5%90%91%E9%87%8Fm%3D%281%2CcosC%2F2%29%2C%E5%90%91%E9%87%8Fn%3D%28%E6%A0%B9%E5%8F%B73sinC%2F2%2BcosC%2F2%2C3%2F2%29%E5%85%B1%E7%BA%BF.1.%E6%B1%82%E8%A7%92C2.%E6%BB%A1%E8%B6%B32acosC%2Bc%3D2b%2C%E8%AF%95%E5%88%A4%E6%96%AD%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%BD%A2%E7%8A%B6.)
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