已知,在等边三角形ABC中,D,E分别为BC,AC上的点,且AE=CD,连结AD,BE交于点P,作BQ垂已知,在等边三角形ABC中,D,E分别为BC,AC上的点,且AE=CD,连结AD,BE交于点P,作BQ垂组为Q,求证BP=2PQ没图,各位就自己画一下吧
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![已知,在等边三角形ABC中,D,E分别为BC,AC上的点,且AE=CD,连结AD,BE交于点P,作BQ垂已知,在等边三角形ABC中,D,E分别为BC,AC上的点,且AE=CD,连结AD,BE交于点P,作BQ垂组为Q,求证BP=2PQ没图,各位就自己画一下吧](/uploads/image/z/5178618-18-8.jpg?t=%E5%B7%B2%E7%9F%A5%2C%E5%9C%A8%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CD%2CE%E5%88%86%E5%88%AB%E4%B8%BABC%2CAC%E4%B8%8A%E7%9A%84%E7%82%B9%2C%E4%B8%94AE%3DCD%2C%E8%BF%9E%E7%BB%93AD%2CBE%E4%BA%A4%E4%BA%8E%E7%82%B9P%2C%E4%BD%9CBQ%E5%9E%82%E5%B7%B2%E7%9F%A5%2C%E5%9C%A8%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CD%2CE%E5%88%86%E5%88%AB%E4%B8%BABC%2CAC%E4%B8%8A%E7%9A%84%E7%82%B9%2C%E4%B8%94AE%3DCD%2C%E8%BF%9E%E7%BB%93AD%2CBE%E4%BA%A4%E4%BA%8E%E7%82%B9P%2C%E4%BD%9CBQ%E5%9E%82%E7%BB%84%E4%B8%BAQ%2C%E6%B1%82%E8%AF%81BP%3D2PQ%E6%B2%A1%E5%9B%BE%2C%E5%90%84%E4%BD%8D%E5%B0%B1%E8%87%AA%E5%B7%B1%E7%94%BB%E4%B8%80%E4%B8%8B%E5%90%A7)
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