在三角形ABC中,已知向量AB·AC=3BA·BC(1)求证:tanB=3tanA (2)若cosC=√5/5,求A的值
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![在三角形ABC中,已知向量AB·AC=3BA·BC(1)求证:tanB=3tanA (2)若cosC=√5/5,求A的值](/uploads/image/z/5195189-29-9.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8FAB%C2%B7AC%3D3BA%C2%B7BC%281%29%E6%B1%82%E8%AF%81%3AtanB%3D3tanA+%282%29%E8%8B%A5cosC%3D%E2%88%9A5%2F5%2C%E6%B1%82A%E7%9A%84%E5%80%BC)
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