作业帮[1/(cos10°)]-[ (根号3)/(sin80°)]=___
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/10 17:05:29
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[1/(cos10°)]-[ (根号3)/(sin80°)]=___
[1/(cos10°)]-[ (根号3)/(sin80°)]=___
[1/(cos10°)]-[ (根号3)/(sin80°)]=___
1/(cos10°) - √3/(sin80°)
= 1/(sin(90°-10°) - √3/(sin80°)
= (1-√3)/(sin80°)
如果没有其他条件,这就是最终结果了
tan70°cos10°【根号3tan20°—1】
化简1／sin10°-根号3／cos10°
化简：1/(sin10°) —根号3/cos10°
1/sin10°-根号3/cos10°=
1/sin10°减去根号3/cos10°,求过程.
求1/sin10°-根号3/cos10°的值.
[1/(cos10°)]-[ (根号3)/(sin80°)]=___
求值：1/sin10°-根号3/cos10°=
急求1/cos10°-根号3/sin80°
求值 1/sin10°-根号3/cos10°
计算1/(sin10°)-(根号3)/(cos10°)的值.
tan70°cos10（根号3tan20°-1)=?
化简sin10°-根号3*cos10°
化简 根号下1+cos10°
化简:cos10(根号3tan20-1)
化简tan70*cos10(根号3tan20-1)
tan 70cos10(根号3tan20-1)
根号（1-2sin10°cos10°）/（cos10°-根号1-cos^2170°）