设数列{An}前n项和为Sn=2n方,{Bn}为等比数列,且a1=b1,b2(a2-a1)=b1,(1)求数列{An},{Bn}通项公式.
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![设数列{An}前n项和为Sn=2n方,{Bn}为等比数列,且a1=b1,b2(a2-a1)=b1,(1)求数列{An},{Bn}通项公式.](/uploads/image/z/5210497-1-7.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7BAn%7D%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%3D2n%E6%96%B9%2C%7BBn%7D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E4%B8%94a1%3Db1%2Cb2%28a2-a1%29%3Db1%2C%EF%BC%881%EF%BC%89%E6%B1%82%E6%95%B0%E5%88%97%7BAn%7D%2C%7BBn%7D%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F.)
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