已知在直三棱柱ABC-A1B1C1中2,(有图)已知在直三棱柱ABC-A1B1C1中,∠BAC=30度,∠ACB=90度,BC=1,AA1=√6(1)求证:面AB1C1⊥面AA1C1C(2)求AB1与面AA1C1C所成角(用反正弦函数表示)arcsin√10/10(3)已知点M为CC1的中点,求
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![已知在直三棱柱ABC-A1B1C1中2,(有图)已知在直三棱柱ABC-A1B1C1中,∠BAC=30度,∠ACB=90度,BC=1,AA1=√6(1)求证:面AB1C1⊥面AA1C1C(2)求AB1与面AA1C1C所成角(用反正弦函数表示)arcsin√10/10(3)已知点M为CC1的中点,求](/uploads/image/z/5226233-41-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%A8%E7%9B%B4%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD2%2C%28%E6%9C%89%E5%9B%BE%29%E5%B7%B2%E7%9F%A5%E5%9C%A8%E7%9B%B4%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2C%E2%88%A0BAC%3D30%E5%BA%A6%2C%E2%88%A0ACB%3D90%E5%BA%A6%2CBC%3D1%2CAA1%3D%E2%88%9A6%281%29%E6%B1%82%E8%AF%81%3A%E9%9D%A2AB1C1%E2%8A%A5%E9%9D%A2AA1C1C%282%29%E6%B1%82AB1%E4%B8%8E%E9%9D%A2AA1C1C%E6%89%80%E6%88%90%E8%A7%92%28%E7%94%A8%E5%8F%8D%E6%AD%A3%E5%BC%A6%E5%87%BD%E6%95%B0%E8%A1%A8%E7%A4%BA%29arcsin%E2%88%9A10%2F10%283%29%E5%B7%B2%E7%9F%A5%E7%82%B9M%E4%B8%BACC1%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E6%B1%82)
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