已知f(x+1)=x2-3x+2求f(a)的值 f(a)=f((a-1)+1)=(a-1)2-3*((a-1)+2=a2-5a+6 为什么 f(x+1)和f(a)括号里的值不是相等的么 为什么不直接把a带入 的a2-3a+2还求f(x)与f(x-1)的解析式 我
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![已知f(x+1)=x2-3x+2求f(a)的值 f(a)=f((a-1)+1)=(a-1)2-3*((a-1)+2=a2-5a+6 为什么 f(x+1)和f(a)括号里的值不是相等的么 为什么不直接把a带入 的a2-3a+2还求f(x)与f(x-1)的解析式 我](/uploads/image/z/5249791-55-1.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%2B1%29%3Dx2-3x%2B2%E6%B1%82f%EF%BC%88a%EF%BC%89%E7%9A%84%E5%80%BC+f%EF%BC%88a%EF%BC%89%3Df%EF%BC%88%EF%BC%88a-1%EF%BC%89%2B1%EF%BC%89%3D%EF%BC%88a-1%EF%BC%892-3%2A%EF%BC%88%EF%BC%88a-1%EF%BC%89%2B2%3Da2-5a%2B6+%E4%B8%BA%E4%BB%80%E4%B9%88+f%EF%BC%88x%2B1%EF%BC%89%E5%92%8Cf%EF%BC%88a%EF%BC%89%E6%8B%AC%E5%8F%B7%E9%87%8C%E7%9A%84%E5%80%BC%E4%B8%8D%E6%98%AF%E7%9B%B8%E7%AD%89%E7%9A%84%E4%B9%88+%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%8D%E7%9B%B4%E6%8E%A5%E6%8A%8Aa%E5%B8%A6%E5%85%A5+%E7%9A%84a2-3a%2B2%E8%BF%98%E6%B1%82f%EF%BC%88x%EF%BC%89%E4%B8%8Ef%EF%BC%88x-1%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F+%E6%88%91)
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