AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF该图形是个5边形,AF平分角BAE、
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 19:12:35
![AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF该图形是个5边形,AF平分角BAE、](/uploads/image/z/5252659-43-9.jpg?t=AB%3DAE%2CBC%3DED%2C%E2%88%A0B%3D%E2%88%A0E%2CAF%E5%9E%82%E7%9B%B4CD%E4%BA%8EF%2C%E6%B1%82%E8%AF%81%EF%BC%9ACF%3DDF%E8%AF%A5%E5%9B%BE%E5%BD%A2%E6%98%AF%E4%B8%AA5%E8%BE%B9%E5%BD%A2%2CAF%E5%B9%B3%E5%88%86%E8%A7%92BAE%E3%80%81)
x)stutqruuyԱH8=|g'tmlzYn.n//}:{ӽXd*v9 =;7?h{|F"}r#;{y::8Og/xcV[:^kIFfT4T";k;_nx:cjyzƓ}Ov}kާ:/.H̳
x
AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF该图形是个5边形,AF平分角BAE、
AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF
该图形是个5边形,AF平分角BAE、
AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF该图形是个5边形,AF平分角BAE、
连接AC,AD
因为AB=AE,BC=ED,∠B=∠E
所以⊿ABC≌⊿AED
所以 AC=AD
又因为AF垂直CD于F,
所以 CF=DF(等腰三角形的高与中线重合)
已知:如图,AB=AE,BC=ED,AF垂直平分CD.求证:∠B=∠E.
如图 ab=ae bc=ed af垂直平分cd 求证 ∠b=∠e
已知:如图,AB=AE,BC=ED,AF是CD的垂直平分线,求证:∠B=∠E
如图,AB=AE,BC=ED,∠B=∠E,∠BAF=∠EAF,求证AF垂直CD
如图,AB=AE,BC=ED,∠B=∠E,∠BAF=∠EAF,求证AF⊥CD
如图,已知AB=AE,BC=ED,∠B=∠E,AF平分∠BAE.求证:CF=DF.
如图已知,AB=AE,BC=ED,∠B=∠E,AF⊥CD于点F,求证CF=DF.
已知:如图,AB=AE,∠B=∠E,BC=ED,CF=DF.求证:AF⊥CD.
已知,如图AB=AE,BC=ED,∠B=∠E,AF⊥CD.F是垂足.求证CF=DF
已知,如图,AB=AE,∠B=∠E,BC=ED,CF=DF,求证AF⊥CD
如图,AB=AE,BC=ED,∠B=∠E,AF⊥CD于F.求证CF=DF.
如图,AB=AE,BC=ED,∠B=∠E,AF⊥CD于F.求证:CF=DF速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求速求~
已知,如图,AB=AE,BC=ED,∠B=∠E,AF⊥CD,求证:F是CD的中点
已知,如图,AB=AE,BC=ED,∠B=∠E,F是CD的中点,求证:AF⊥CD
已知:如图,AB=AE,∠B=∠E,BC=ED,F是CD的中点.求证:AF⊥CD
AB=AE ,BC=ED ,F是CD中点,AF⊥CD,求∠B=∠E一定要写清步骤
五边形ABCDE,AB=AE,BC=ED,AF是CD的垂直平分线,求证:角B=角E.XIEXIE
已知,如图,ab=ae,bc=ed,∠b=∠e,af⊥cd,垂足为f.求证:cf=df 可画辅助已知,如图,ab=ae,bc=ed,∠b=∠e,af⊥cd,垂足为f.求证:cf=df可画辅助线