[(x+ay)dx+4ydy]/(x+2y) 为某函数u(x,y)的全微分,求a

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 17:56:50
[(x+ay)dx+4ydy]/(x+2y) 为某函数u(x,y)的全微分,求a
x)~B;Δ mʔX} mJM';v=?igS7T=u}v<ؔhTO c l枔R[&UWښTBEl5L**t*4a"F@wV>_h=Jm*u+r 0C+luaº00/x>{ݓ@l @~#9

[(x+ay)dx+4ydy]/(x+2y) 为某函数u(x,y)的全微分,求a
[(x+ay)dx+4ydy]/(x+2y) 为某函数u(x,y)的全微分,求a

[(x+ay)dx+4ydy]/(x+2y) 为某函数u(x,y)的全微分,求a
du=[(x+ay)dx+4ydy]/(x+2y)
u'y=4y/(x+2y)=(4y+2x-2x)/(x+2y)=2-2x/(x+2y)
对y积分:u=2y-xln(x+2y)+g(x)
u'x=-ln(x+2y)-x/(x+2y)+g'(x)
题目不对