数列an的前n项和Sn且满足Sn=4/3an-1/3*2^n+1+2/3,1)求数列的首项a1与通项Sn(2)设数列bn=2^n/Sn的前项和为Tn求证Tn
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 14:02:33
![数列an的前n项和Sn且满足Sn=4/3an-1/3*2^n+1+2/3,1)求数列的首项a1与通项Sn(2)设数列bn=2^n/Sn的前项和为Tn求证Tn](/uploads/image/z/5326740-36-0.jpg?t=%E6%95%B0%E5%88%97an%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%E4%B8%94%E6%BB%A1%E8%B6%B3Sn%3D4%2F3an-1%2F3%2A2%5En%2B1%2B2%2F3%2C1%29%E6%B1%82%E6%95%B0%E5%88%97%E7%9A%84%E9%A6%96%E9%A1%B9a1%E4%B8%8E%E9%80%9A%E9%A1%B9Sn%282%29%E8%AE%BE%E6%95%B0%E5%88%97bn%3D2%5En%2FSn%E7%9A%84%E5%89%8D%E9%A1%B9%E5%92%8C%E4%B8%BATn%E6%B1%82%E8%AF%81Tn)
xTmk@*AKЉMDl|̗2Dˊ,bm P
(KozMrwӵڬelq5l]Hd?WBȋQyW F8Mv&|$VIDL`PH4SuZ_"<*j֪ULl8^9BnE5ߺ&+uel(ߝ"44EL2ېYpY3a}vKlAޗ{Uz?H7e <0Q*̂ʐwtc[ |G%6A:<#Ok6؇v;!y̧\tOh?ȳ]c)"w,Irq䪺+HŅTo2YtXr6'Ʉgd l`ٍIi`dn|>ɗmn