谢 BE,CF是△ABC的中线,BE,CF相交于点G 求证:GE/GB=GF/GC=1/2证明:如图,连接FE ∵E,F分别为AC,AB中点∴EF‖BC,EF=1/2BC ∴GE/GB=GF/GC=EF/BC=1/2.阅读上面证明过程填空:(1)如果M.N分别为GB.GC中点,则四边形E
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![谢 BE,CF是△ABC的中线,BE,CF相交于点G 求证:GE/GB=GF/GC=1/2证明:如图,连接FE ∵E,F分别为AC,AB中点∴EF‖BC,EF=1/2BC ∴GE/GB=GF/GC=EF/BC=1/2.阅读上面证明过程填空:(1)如果M.N分别为GB.GC中点,则四边形E](/uploads/image/z/5329759-31-9.jpg?t=%E8%B0%A2+BE%2CCF%E6%98%AF%E2%96%B3ABC%E7%9A%84%E4%B8%AD%E7%BA%BF%2CBE%2CCF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9G+%E6%B1%82%E8%AF%81%EF%BC%9AGE%2FGB%3DGF%2FGC%3D1%2F2%E8%AF%81%E6%98%8E%EF%BC%9A%E5%A6%82%E5%9B%BE%2C%E8%BF%9E%E6%8E%A5FE+%E2%88%B5E%2CF%E5%88%86%E5%88%AB%E4%B8%BAAC%2CAB%E4%B8%AD%E7%82%B9%E2%88%B4EF%E2%80%96BC%2CEF%3D1%2F2BC+%E2%88%B4GE%2FGB%3DGF%2FGC%3DEF%2FBC%3D1%2F2.%E9%98%85%E8%AF%BB%E4%B8%8A%E9%9D%A2%E8%AF%81%E6%98%8E%E8%BF%87%E7%A8%8B%E5%A1%AB%E7%A9%BA%EF%BC%9A%EF%BC%881%EF%BC%89%E5%A6%82%E6%9E%9CM.N%E5%88%86%E5%88%AB%E4%B8%BAGB.GC%E4%B8%AD%E7%82%B9%2C%E5%88%99%E5%9B%9B%E8%BE%B9%E5%BD%A2E)
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