y=in((1-x)/(1+x))求导
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y=in((1-x)/(1+x))求导
y=in((1-x)/(1+x))求导
y=in((1-x)/(1+x))求导
y'=1/[(1-x)/(1+x)]*[(1-x)/(1+x)]'=(1+x)/(1-x)*[2/(1+x)-1]'=(1+x)/(1-x)*2*(-1)(1+x)^(-2)
=-2/(x+1)(1-x)=2/(x+1)(x-1)
y'=[ln((1-x)/(1+x))]'
=1/[(1-x)/(1+x)]*[(1-x)/(1+x)]'
=(1+x)/(1-x)*[-(1+x)-(1-x)]/(1+x)²
=(1+x)/(1-x)*(-2)/(1+x)²
=-2/[(1-x)(1+x)]
=2/[(x+1)(x-1)]