lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法如果错了请教教我怎麽解和解的过程.
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![lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法如果错了请教教我怎麽解和解的过程.](/uploads/image/z/5352247-55-7.jpg?t=lim%28x%E2%86%920%29%5Btan%282x%2Bx%5E3%29%2Fsin%28x-x%5E2%29%5D+%E5%92%8Clim%28x%E2%86%920%29%5B%28x-sinx%29%2F%28x%2Bsinx%29%5D%E7%9A%84%E7%AD%94%E6%A1%88%E5%92%8C%E8%A7%A3%E6%B3%95%E5%A6%82%E6%9E%9C%E9%94%99%E4%BA%86%E8%AF%B7%E6%95%99%E6%95%99%E6%88%91%E6%80%8E%E9%BA%BD%E8%A7%A3%E5%92%8C%E8%A7%A3%E7%9A%84%E8%BF%87%E7%A8%8B.)
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lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法如果错了请教教我怎麽解和解的过程.
lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法
如果错了请教教我怎麽解和解的过程.
lim(x→0)[tan(2x+x^3)/sin(x-x^2)] 和lim(x→0)[(x-sinx)/(x+sinx)]的答案和解法如果错了请教教我怎麽解和解的过程.
第一题利用等价无穷小法则
lim(x→0)[tan(2x+x^3)/sin(x-x^2)]
=lim(x→0)[(2x+x^3)/(x-x^2)]=0
第二题分子分母同时除以x
lim(x→0)[(x-sinx)/(x+sinx)]
=lim(x→0)[(1-(sinx/x))/(1+(sinx/x))]然后利用等价无穷小
=lim(x→0)[(1-1)/(1+1)]=0
lim(x→0)[tan(2x+x^3)/sin(x-x^2)]
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