麻烦数学好的进来、、、如图1,一个直角三角形ABC的木框和一个端点为O且可任意调整角度的角尺,其中∠ACB=90°,∠A=∠a.如图4使角尺的两边分别与ABC的两边直,即OD⊥AC于D,DE ⊥AB并交BA的延长线
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![麻烦数学好的进来、、、如图1,一个直角三角形ABC的木框和一个端点为O且可任意调整角度的角尺,其中∠ACB=90°,∠A=∠a.如图4使角尺的两边分别与ABC的两边直,即OD⊥AC于D,DE ⊥AB并交BA的延长线](/uploads/image/z/5377094-62-4.jpg?t=%E9%BA%BB%E7%83%A6%E6%95%B0%E5%AD%A6%E5%A5%BD%E7%9A%84%E8%BF%9B%E6%9D%A5%E3%80%81%E3%80%81%E3%80%81%E5%A6%82%E5%9B%BE1%2C%E4%B8%80%E4%B8%AA%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E6%9C%A8%E6%A1%86%E5%92%8C%E4%B8%80%E4%B8%AA%E7%AB%AF%E7%82%B9%E4%B8%BAO%E4%B8%94%E5%8F%AF%E4%BB%BB%E6%84%8F%E8%B0%83%E6%95%B4%E8%A7%92%E5%BA%A6%E7%9A%84%E8%A7%92%E5%B0%BA%2C%E5%85%B6%E4%B8%AD%E2%88%A0ACB%3D90%C2%B0%2C%E2%88%A0A%3D%E2%88%A0a.%E5%A6%82%E5%9B%BE4%E4%BD%BF%E8%A7%92%E5%B0%BA%E7%9A%84%E4%B8%A4%E8%BE%B9%E5%88%86%E5%88%AB%E4%B8%8EABC%E7%9A%84%E4%B8%A4%E8%BE%B9%E7%9B%B4%2C%E5%8D%B3OD%E2%8A%A5AC%E4%BA%8ED%2CDE+%E2%8A%A5AB%E5%B9%B6%E4%BA%A4BA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF)
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