log2（x^-x-2）>2 怎么算

log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8) log2（x^-x-2）>2 怎么算 log2底x^2怎么算 log2^x怎么算 |2x-log2^x| log2^x*log2^2x=2 这个要怎么算?、 |[log2(x)]^2-3log2(x)+1| 化简：(log2(x/4))*(log2(x/2)) log2(2X-1) log2(x^2)图像 log2(x-2) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 f(x)=(log2^x)^2-log2^x+2怎么解 log2(4*-x+1)怎么等于log2(4*x+1)-2x 不等式|2x-log2^x| 已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f（x）=log2（2x）×log2（x／4）＝[（log2 2）+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2 log2(2x)*log2(x)=2 x=? f(x)=log2(x/8)*log2(2/x)