sin(π/4+α)=√3/2 则sin(3π/4-α)值为

sin(π/4+α)=√3/2 则sin(3π/4-α)值为 化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)= 已知sin(3π-α)=-2sin(π/2+α)则sinαcosα 已知sin(α+π/3)+sinα=-4√3/5(-π/2 已知sin(π/4+α)=√3/2,则sin(3π/4-α)值为 2sin(α+π/3）=sinα+______ sin(π-α)=-2sin(π/2+α),则sinαcosα等于 sin(3∏-α）=-2sin（Π∕2+α)则sinαcosα等于 若sin(α+β)=1/2,sinαcosβ=3/4,则sin(α-β)= 若（sinα+cosα）/（sinα-cosα）=2 则sin(α-5π)·sin(3π/2-α)=? 若sinα+cosα/sinα-cosα=2,则sin(α-5π）*sin（3π/2-α）等于? 2sinα-3cosα/4sinα-9cosα=-1,则9sin^2α-3sinαcosα-5= sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/ 若sin(π+α)+sin(-α)=-m,则sin（3π+a)+2sin(2π-a)的值为? 若sin^2β-sin^2α=m,则sin(α+β)sin(α-β) 求值：（tan10°-√3）×cos10°/sin50° 求证：[sin（2α+β）]/sinα- 2cos（α+β）=sinβ/cosα 化简cosθ+cos（θ+2π/3）+cos（θ+4π/3） 证明：sin（α+β）sin（α-β）=sin^2α-sin^2β 已知tan(π+α)=3,则2cos(π-α)-3sin(π+α)/4sin(α+π/2)+sin(2π-α)= 已知3sin²α+2sin²β=2sinα,求cos²α+cos²β的取值范围已知3sin²α+2sin²β=2sinα则有2sin²β=2sinα-3sin²α即sin²β=sinα-1.5sin²α所以cos²β=1-sin²β=1-(sinα-1.5sin²α)=1-