等差数列an的前n项和为sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=等差数列an的前n项和为Sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=cos(2011π\6),则S2013

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等差数列an的前n项和为sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=等差数列an的前n项和为Sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=cos(2011π\6),则S2013
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等差数列an的前n项和为sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=等差数列an的前n项和为Sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=cos(2011π\6),则S2013
等差数列an的前n项和为sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=
等差数列an的前n项和为Sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=cos(2011π\6),则S2013等于( ).
A.2013
B.4026
C.0
D.2013根号下三

等差数列an的前n项和为sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=等差数列an的前n项和为Sn,已知(a2-1)^3+2012(a2-1)=sin(2011π\3),(a2012-1)^3+2012(a2012-1)=cos(2011π\6),则S2013
(a2-1)³+2012(a2-1)=sin(2011π/3)=sin(π/3)=√3/2
(a2012-1)³+2012(a2012-1)=cos(2011π/6)=cos(7π/6)=-√3/2
(a2-1)³+2012(a2-1)+(a2012-1)³+2012(a2012-1)=0
[(a2-1)³+(a2012-1)³]+2012[(a2-1)+(a2012-1)]=0
[(a2-1)+(a2012-1)][(a2-1)²-(a2-1)(a2012-1)+(a2012-1)²+2012]=0
(a2-1)²-(a2-1)(a2012-1)+(a2012-1)²+2012恒>0,因此只有
(a2-1)+(a2012-1)=0
a2+a2012=2
S2013=(a1+a2013)×2013/2=(a2+a2012)×2013/2=2×2013/2=2013
选A.