matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
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![matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100](/uploads/image/z/5436013-13-3.jpg?t=matlab%E6%B1%82%E5%87%BD%E6%95%B0%E6%9B%B2%E7%BA%BF%E7%9A%84%E7%A7%AF%E5%88%86+%E8%AF%B7%E9%97%AE%2C%E6%80%8E%E4%B9%88%E5%BC%84%E6%89%8D%E8%83%BD%E5%87%BA%E7%9C%9F%E7%A1%AE%E7%BB%93%E6%9E%9Csyms+x+tf1%3Dsqrt%281%2B%28155%2A2%2Api%2Ft%2Acos%282%2Api%2Ft%2A%28x-350%29%29%29.%5E2%29int%28f1%2Cx%29f1+%3D%28%2896100%2Api%5E2%2Acos%28%282%2Api%2A%28x+-+350%29%29%2Ft%29%5E2%29%2Ft%5E2+%2B+1%29%5E%281%2F2%29Warning%3AExplicit+integral+could+not+be+found.ans+%3Dint%28%28%2896100)
matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
matlab求函数曲线的积分 请问,怎么弄才能出真确结果
syms x t
f1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)
int(f1,x)
f1 =
((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)
Warning:Explicit integral could not be found.
ans =
int(((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2),x)
matlab求函数曲线的积分 请问,怎么弄才能出真确结果syms x tf1=sqrt(1+(155*2*pi/t*cos(2*pi/t*(x-350))).^2)int(f1,x)f1 =((96100*pi^2*cos((2*pi*(x - 350))/t)^2)/t^2 + 1)^(1/2)Warning:Explicit integral could not be found.ans =int(((96100
积分后,得到
-1/2*(1-cos(2*pi/t*(x-350))^2)^(1/2)*EllipticE(cos(2*pi/t*(x-350)),310*pi*(-1/t^2)^(1/2))/sin(2*pi/t*(x-350))/pi*t
式中,EllipticE为椭圆函数