解决一道因式分解的化简题化简(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
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解决一道因式分解的化简题化简(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
解决一道因式分解的化简题
解决一道因式分解的化简题化简(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
第一步,提取前两项的(a-b)(a+b)
原式=(a-b)(a+b)[(a+b)-(a-b)]+2b(a²+b²)
=(a²-b²)(2b)+2b(a²+b²)
=2b(a²-b²+a²+b²)
=2b*2a²
=4a²b
原式=(a²-b²)(a+b)-(a²-b²)(a-b)+2b(a²+b²)
=2b(a²-b²)+2b(a²+b²)
=2b(a²-b²+a²+b²)
=2ab²
(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
=(a-b)(a+b)[(a+b)-(a-b)]+2b(a²+b²)
=(a²-b²)(a+b-a+b)+2b(a²+b²)
=2b(a²-b²)+2b(a²+b²)
=2b[(a²-b²)+(a²+b²)]
=2b(a²-b²+a²+b²)
=4a²b;
=(a+b)(a-b)[(a+b)-(a-b)]+2b(a²+b²)
=2b(a²-b²)+2b(a²+b²)
=2b(a²-b²+a²+b²)
=4a²b
(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
=(a-b)(a+b)[(a+b)-(a-b)]+2b(a²+b²)
=2b(a-b)(a+b)+2b(a²+b²)
=2b(a²-b²)+2b(a²+b²)
=2b[(a²-b²)+(a²+b²)]
=2b*2a²
=4a²b
(a-b)(a+b)²-(a+b)(a-b)²+2b(a²+b²)
=(a-b)(a+b)²+2b(a²+b²)-(a+b)(a-b)²
=(a+b)(a²-b²)+2a(a²+b²)-(a-b)(a²-b²)
=(a²-b²+a²-b²)(a+b-a+b)
=2(a²+b²)*2b
=4b(a²+b²)