急 设a1,a2,a3是互不相等的常数,求方程组(x1)+(a1)(x2)+(a1)^2(x3)=1,(x1)+(a2)(x求方程组(x1)+(a1)(x2)+(a1)^2(x3)=1,(x1)+(a2)(x2)+(a2)^2(x3)=1,(x1)+(a3)(x2)+(a3)^2(x3)=1,
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![急 设a1,a2,a3是互不相等的常数,求方程组(x1)+(a1)(x2)+(a1)^2(x3)=1,(x1)+(a2)(x求方程组(x1)+(a1)(x2)+(a1)^2(x3)=1,(x1)+(a2)(x2)+(a2)^2(x3)=1,(x1)+(a3)(x2)+(a3)^2(x3)=1,](/uploads/image/z/5464693-37-3.jpg?t=%E6%80%A5+%E8%AE%BEa1%2Ca2%2Ca3%E6%98%AF%E4%BA%92%E4%B8%8D%E7%9B%B8%E7%AD%89%E7%9A%84%E5%B8%B8%E6%95%B0%2C%E6%B1%82%E6%96%B9%E7%A8%8B%E7%BB%84%28x1%29%2B%28a1%29%28x2%29%2B%28a1%29%5E2%28x3%29%3D1%2C%28x1%29%2B%28a2%29%28x%E6%B1%82%E6%96%B9%E7%A8%8B%E7%BB%84%28x1%29%2B%28a1%29%28x2%29%2B%28a1%29%5E2%28x3%29%3D1%2C%28x1%29%2B%28a2%29%28x2%29%2B%28a2%29%5E2%28x3%29%3D1%2C%28x1%29%2B%28a3%29%28x2%29%2B%28a3%29%5E2%28x3%29%3D1%2C)
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