作业帮求lim(x->0)( x^2-∫(0-x^2)cos(t^2))/(sinx)^10,积分是0到x^2，写成∫(0-x^2)这样了，
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/20 23:13:30
xn@_%ɑw?JrkC:Bd i@JH]*{mN}Hs.fF34zҠւTq6.A-~nH
ޠVA:H8$̋nh"l3E幆G g+
f{zRϚevd \E=Lf~ >zV] (zM Pbh-l`TUp16t1@%騊fF4P9 m:a Gbk:P6c@TD!bt %K~fxF|ￊU^ h$ƫ߫KzRΆ] ˣt:^im\MgrޮhZw!
求lim(x->0)( x^2-∫(0-x^2)cos(t^2))/(sinx)^10,积分是0到x^2，写成∫(0-x^2)这样了，
求lim(x->0)( x^2-∫(0-x^2)cos(t^2))/(sinx)^10,
积分是0到x^2，写成∫(0-x^2)这样了，
求lim(x->0)( x^2-∫(0-x^2)cos(t^2))/(sinx)^10,积分是0到x^2，写成∫(0-x^2)这样了，
若不断用洛必达法则也挺麻烦的.考虑一下等价无穷小吧.
求极限lim(x->0)(x+e^x)^2/x
求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0
求极限 lim/x-0 (e^x+sinx+x^2)
求极限lim(x-->0)x^2 sin(1/x),
x趋于0时,求lim(x-tanx)/x^2,
lim(1+2x)^1/x求极限（lim下是x~0)
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
lim x-0 sin2x/x 求极限
lim(x->0)arctan1/x求极限
求极限lim(x->0)x^sinx,
lim(1-x)^(2/x) x->0
求极限 lim x-0 sinx/2x =?过程
求极限lim【1-cosmx)/x^2】,x趋向0
求lim x趋向于0(arctanx)/(x^2+1)
求极限lim x-0 2x/sinx
lim x->0(sqrt(sin(1/x^2)) 求极限
lim 2x/tan3x x→0 求极限
lim 1/2x x-->0 求极限