已知{an}是正数组成的数列,a1=1,且点(根号an,a(n+1))(n∈N*)在函数y=x^2+1的图像上(1)求数列{an}的通项公式(2)若数列{bn}满足b1=1,b(n+1)=bn+2^an,求证bn*b(n+2)<b(n+1)的平方有个答案是An+1=A(n+1),所以
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![已知{an}是正数组成的数列,a1=1,且点(根号an,a(n+1))(n∈N*)在函数y=x^2+1的图像上(1)求数列{an}的通项公式(2)若数列{bn}满足b1=1,b(n+1)=bn+2^an,求证bn*b(n+2)<b(n+1)的平方有个答案是An+1=A(n+1),所以](/uploads/image/z/5557973-5-3.jpg?t=%E5%B7%B2%E7%9F%A5%7Ban%7D%E6%98%AF%E6%AD%A3%E6%95%B0%E7%BB%84%E6%88%90%E7%9A%84%E6%95%B0%E5%88%97%2Ca1%3D1%2C%E4%B8%94%E7%82%B9%EF%BC%88%E6%A0%B9%E5%8F%B7an%2Ca%28n%2B1%29%29%28n%E2%88%88N%2A%29%E5%9C%A8%E5%87%BD%E6%95%B0y%3Dx%5E2%2B1%E7%9A%84%E5%9B%BE%E5%83%8F%E4%B8%8A%EF%BC%881%EF%BC%89%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E8%8B%A5%E6%95%B0%E5%88%97%7Bbn%7D%E6%BB%A1%E8%B6%B3b1%3D1%2Cb%28n%2B1%29%3Dbn%2B2%5Ean%2C%E6%B1%82%E8%AF%81bn%2Ab%28n%2B2%29%EF%BC%9Cb%EF%BC%88n%2B1%29%E7%9A%84%E5%B9%B3%E6%96%B9%E6%9C%89%E4%B8%AA%E7%AD%94%E6%A1%88%E6%98%AFAn%2B1%3DA%28n%2B1%29%2C%E6%89%80%E4%BB%A5)
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