y=根号下[(1/2)^x-1]的单调区间怎么求啊!?y=根号下[(1/2)^x-1](1/2)^x-1≥0x∈(-∞,0]t=(1/2)^x单调递减 在(-∞,0]单调递减y=根号下(t-1)t∈[1,+∞)单调递增所以x∈(-∞,0]单调递减这是我的
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![y=根号下[(1/2)^x-1]的单调区间怎么求啊!?y=根号下[(1/2)^x-1](1/2)^x-1≥0x∈(-∞,0]t=(1/2)^x单调递减 在(-∞,0]单调递减y=根号下(t-1)t∈[1,+∞)单调递增所以x∈(-∞,0]单调递减这是我的](/uploads/image/z/5565344-32-4.jpg?t=y%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%281%2F2%EF%BC%89%5Ex-1%5D%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4%E6%80%8E%E4%B9%88%E6%B1%82%E5%95%8A%21%3Fy%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%281%2F2%EF%BC%89%5Ex-1%5D%EF%BC%881%2F2%EF%BC%89%5Ex-1%E2%89%A50x%E2%88%88%EF%BC%88-%E2%88%9E%2C0%5Dt%3D%EF%BC%881%2F2%EF%BC%89%5Ex%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F+%E5%9C%A8%EF%BC%88-%E2%88%9E%2C0%5D%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8Fy%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%88t-1%EF%BC%89t%E2%88%88%5B1%2C%2B%E2%88%9E%EF%BC%89%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E6%89%80%E4%BB%A5x%E2%88%88%EF%BC%88-%E2%88%9E%2C0%5D%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%E8%BF%99%E6%98%AF%E6%88%91%E7%9A%84)
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