(x+20)×0.8=x-12怎么解?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 19:22:17
(x+20)×0.8=x-12怎么解?
xSn@QJWL8,?7ژ:U@h(,XТJe韠IWflP;9{*8x_$jLGkUs [Z?sI/`PT ,}Pz.߬eIbyDb(P;*AU|` x>(#~*$ JTf2*p6ցu{sn5oux[kZpF&wĽ܀MxBo !9Khۂn 5 b&iѺFM sAm%ʹ-WZ_KIS^s/2׉+j#,HTP^`z|KN2V' -J&TtGt>6pE6d zjy:x{J9/j|Q I?z;?mo'qpϋ]iq4$wK;7ܙDO>XB:;G Z2j,{p-;fb%&.N&ыr:O4'4

(x+20)×0.8=x-12怎么解?
(x+20)×0.8=x-12怎么解?

(x+20)×0.8=x-12怎么解?
0.8x+16=x-12
0.2x=28
x=140

答案是:
(x+20)×0.8=x-12
0.8x +(20)(0.8) = x -12
16 + 12 = x -0.8x
28 = 0.2x
x = 28/0.2 = 140
谢谢

﹙x+20)×0.8≒x-12
0.8x+16=x-12
16+12=x-0.8x
所以0.2x=28 ,解得,x=28÷0.2=140
互帮互助,满意请采纳哦!

(x+20)×0.8=x-12
解:
去括号,得0.8x+16=x-12
移项,得0.8x-x=-12-16
合并同类项,-0.2x=-28
系数化为一,得x=140