已知an=(n+1)²分之一(n=1,2,3,...),记b1=2(1-a),b2=2(1-a)(1-a),...,bn=2(1-a1)(1-a2)...(1-an),则通则通过计算推测出bn的表达式bn=(?)(用含n的代数式表示)
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![已知an=(n+1)²分之一(n=1,2,3,...),记b1=2(1-a),b2=2(1-a)(1-a),...,bn=2(1-a1)(1-a2)...(1-an),则通则通过计算推测出bn的表达式bn=(?)(用含n的代数式表示)](/uploads/image/z/5596476-60-6.jpg?t=%E5%B7%B2%E7%9F%A5an%3D%28n%2B1%29%26sup2%3B%E5%88%86%E4%B9%8B%E4%B8%80%28n%3D1%2C2%2C3%2C...%29%2C%E8%AE%B0b1%3D2%281-a%29%2Cb2%3D2%281-a%29%281-a%29%2C...%2Cbn%3D2%281-a1%29%281-a2%29...%281-an%29%2C%E5%88%99%E9%80%9A%E5%88%99%E9%80%9A%E8%BF%87%E8%AE%A1%E7%AE%97%E6%8E%A8%E6%B5%8B%E5%87%BAbn%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8Fbn%3D%EF%BC%88%3F%EF%BC%89%EF%BC%88%E7%94%A8%E5%90%ABn%E7%9A%84%E4%BB%A3%E6%95%B0%E5%BC%8F%E8%A1%A8%E7%A4%BA%EF%BC%89)
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