先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 23:00:56
先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2
x){gu :OzmlzڰGOP?Q7IHj'iޞhkdhklΧۍl ul"}j_`gCUw}( tx L9\DM(I@( !R0CGt!P6*@<}H.kzӮO[=]rf$ف

先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2
先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2

先化简,再求值.(1/a-b-1/a+b)÷b/a2-2ab+b2 a=1+根号2 b=1-根号2
.(1/a-b-1/a+b)÷b/a2-2ab+b2
=(a+b-a+b)/(a-b)(a+b)÷b/(a-b)²
=2b/(a+b)÷b/(a-b)
=2(a-b)/(a+b)
=2(1+√2-1+√2)/(1+√2+1-√2)
=2x2√2/2
=2√2
如追加其它问题,