作业帮解分式方程:1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/17 01:18:19
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解分式方程:1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
解分式方程:1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
解分式方程:1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
1/(x-3)+1/(x-7)=1/(x-4)+1/(x-6).
1/(x-3)-1/(x-4)=1/(x-6)-1/(x-7)
(x-4-x+3)/(x-3)(x-4)=(x-7-x+6)/(x-6)(x-7)
-1/(x-3)(x-4)=-1/(x-6)(x-7)
(x-6)(x-7)=(x-3)(x-4)
x²-13x+42=x²-7x+12
-6x=-30
x=5
检验：x=5是方程的根
解分式方程：(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)
解分式方程: (x-1)/(x-2)+(x-6)/(x-7)=(x-2)/(x-3)+(x-5)/(x-6)
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